Question

2. Solve for h: h 1 + 5 -3 2 = 17. o 5 h = – 3 -3 6 1 h= -67 2 -67 1 On- h = -34 2 On=-71 /

Answer 1

We are given the following expression:

`(h)/(-3)+5(1)/(2)=17`

We are asked to solve for "h". To do that we will first rewrite the mixed fraction in standard form:

`(h)/(-3)+5+(1)/(2)=17`

Now we add 5 and 1/2, we get:

`(h)/(-3)+(11)/(2)=17`

Now we subtract 11/2 from both sides:

`(h)/(-3)=17-(11)/(2)`

Now we solve the difference:

`(h)/(-3)=(23)/(2)`

Now we multiply both sides by -3:

`h=-(69)/(2)`

Now we rewrite the numerator as follows:

`h=-(68+1)/(2)`

Now we distribute the denominator:

`h=-((68)/(2)+(1)/(2))`

Simplifying we get:

`h=-(34+(1)/(2))`

Now we can write the result as a mixed fraction:

`h=-34(1)/(2)`

And thus we have solved for "h".