Question

An tank contains oxygen (O2) at a pressure of 2.29 atm . What is the pressure in the tank in terms of mmHg? What is the pressure in the tank in kPa?

Answer 1

The pressure of oxygen in the tank is 1739.4 mmHg or 231.93 kPa, after using the respective conversion factors from atm to mmHg and atm to kPa.

The pressure of oxygen in the tank is given as 2.29 atm.

To convert this pressure into mmHg, we use the conversion factor 1 atm = 760 mmHg.

So, multiplying 2.29 atm by 760 mmHg/atm gives us:

2.29 atm × 760 mmHg/atm = 1739.4 mmHg

To convert the pressure into kPa, we use the fact that 1 atm is approximately equal to 101.325 kPa.

Therefore, the pressure in kPa is:

2.29 atm × 101.325 kPa/atm = 231.93 kPa.

Answer 2

Step-by-step explanation:

We have to convert the tanks pressure from atm to mmHg. We know that 1 atm is equal to 760 mmHg. We can use this relationship to find the answer to our problem.

1 atm = 760 mmHg

P = 2.29 atm = 2.29 atm * 760 mmHg/(1 atm)

P = 1740 mmHg

Then 1 atm is equal to 101.325 kPa.

1 atm = 101.325 kPa

P = 2.29 atm = 2.29 atm * 101.325 kPa/(1 atm)

P = 232 kPa

Answer: The pressure is 1740 mmHg or 232 kPa.