Question

The mean is 22.0 and the standard deviation is 2.4.Find the probability that X is between 19.7 and 25.3.

Answer 1

Given:

Mean = μ = 22

Standard deviation = σ = 2.4

We will find the probability that x is between 19.7 and 25.3

We will find the z-score for the given values of x

`\begin{gathered} x=19.7\rightarrow z=(x-\mu)/(\sigma)=(19.7-22)/(2.4)=-0.95833 \\ \\ x=25.3\rightarrow z=(x-\mu)/(\sigma)=(25.3-22)/(2.4)=1.375 \end{gathered}`

So,

`P(19.7So, From the z-table, the probability =[tex]0.33105+0.41543=0.74648`

so, the answer will be 0.74648