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Find a parallel equation to the line f(x) = -5/4x-3 and a perpendicular equation that passes through the point (0, -3).

User Algorowara
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1 Answer

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12 votes

Answer:

y = -5/4 x -3 (Equation of parallel line)

y = 4/5 x - 3 (Equation of perpendicular line)

Step-by-step explanation:

The stanadard form of an equation is expressed as y = mx+c

m is the slope

c is the intercept

Given the equation f(x) = -5/4x-3, the slope of the line is -5/4

If equation of the known line is parallel to the required line, they will have the same slope, that is;

m = -5/4

Get the intercept:

Substitute m = -5/4 and the point (0, -3) into the equation y = mx +c and find c as shown;

-3 = -5/4(0) + c

c = -3

Substitute m = -5/4 and c = 3 into y = mx+c

y = -5/4 x -3 (Equation of parallel line)

If equation of the line is perpendicular to the line, the product of the slope will be -1 i.e

m(-5/4) = -1

m = -1/(-5/4)

m = 4/5

Get the intercept;

substitute m = 4/5 and the point (0, -3) into the equation y = mx+c

-3 = 4/5(0)+c

c = -3

Get the equation;

y = 4/5 x - 3 (Equation of perpendicular line)

User Koningdavid
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