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Which equation has exactly two real and two nonreal solutions?

Which equation has exactly two real and two nonreal solutions?-example-1
User Michael J
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1 Answer

19 votes
19 votes

Given:

Equations are given.

Option B and D only has the 4 solutions.

First taking the option B


\begin{gathered} x^4-12x^2-64=0 \\ x^4+4x^2-16x^2-64=0 \\ x^2(x^2+4)-16(x^2+4)=0 \\ (x^2+4)(x^2-16)=0 \end{gathered}
\begin{gathered} x^2+4=0 \\ x^2=-4 \\ x=\pm2i \end{gathered}
\begin{gathered} x^2-16=0 \\ x^2=16 \\ x=\pm4 \end{gathered}

Option B is the final answer.

User BWG
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