Here are the equations:
63 + 12n =
and
15n =
So we need to figure out when they will meet up at the same value...
63 + 12( )=
and
15 x ( )=
So for this, the starting fee is $63 ahead of the one without the starting fee.
So we find the multiple where each equals the same value...
63 + 12(21)= 315
and
15(21)= 315
12 x 21 = 252
252 + 63 = 315
15 x 21 = 315
So after 21 classes, the cost will be the same.
Hope this helped! :)