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In parallelogram mnpq, side mn is seven inches longer than twice the length of side np if the perimeter of mnpq is 68 inches then determine the length of np

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Opposite sides of a parallelogram are the same length. Let the length of side np = x inches. Side qm is then also x inches. The problem gives the length of side mn in terms of side np as (2*x)+7 inches. Side pq is then also (2*x)+7 inches. The perimeter is the sum of all four sides. x + x + [(2*x)+7] + [(2*x)+7], or 6x + 14 inches. We are given the perimeter measure, so 6x + 14 = 68. Subtract 14 from both sides: 6x = 54. Divide both sides by 6: x = 9 inches. Thus the length of side np is 9 inches.
User Mrugesh Tank
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perimeter of a parallelogram = 2(a+b)
Perimeter of parallelogram mnpq = 68 inches
mn is seven inches longer than twice the length of side np
let the length of np = x
length of mn= 2x + 7
Now,
p = 2(2x+7+x)
68 = 4x + 14 + 2x
68 = 6x + 14
6x = 68 - 14
6x = 54
x = 9
Thus, the length of np is 9 inches.

User KNejad
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