Question

3 times the sum of N and 4 is 12

Answer 1

The sum of n and 4 can be express as:

`n+4`

Three times this sum is:

`3(n+4)`

And this is equal to 12, then:

`3(n+4)=12`

Solving for n, we have:

`\begin{gathered} 3(n+4)=12 \\ 3n+12=12 \\ 3n=12-12 \\ 3n=0 \\ n=(0)/(3) \\ n=0 \end{gathered}`

Therefore, n=0.