Question

It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°C. The specific heat of the substance is 1.2 J/g°C.

Answer 1

I'll assume you are looking for the mass of the object, since that is the missing piece of the puzzle.

The important equation for heat and energy is

Energy = mass × specific heat × change in temperature

Things we know:
Energy needed is 350 J.
Specific heat = 1.2 J/g°C
Temp. change = (30-20)°

Now we just need to plug those in and rearrange the formula to find the mass!

350 = mass × 1.2 × 10

Answer 2

The amount of the substance is 14.6 g.

Step-by-step explanation:

Given that,

Energy = 350 J

Temperature
`T_(1)=10.0^(\circ)\ C`

Temperature
`T_(2)=30.0^(\circ)\ C`

Specific heat capacity = 1.2 J/g^{/circ}[/tex]

We know that,

The formula of specific heat is defined as

`Q = mc\Delta T`

Where,

m = mass of the substance

c = specific heat capacity

`\Delta T` = Temperature change

Put the value into the formula

`350=m* 1.2*(30-10)`

The amount of substance is

`m =(350)/(1.2*(30-10))`

`m =14.6\ g`

Hence, The amount of the substance is 14.6 g.