Question

What total capacitances (in µF) can you make by connecting a 4.45 µF and an 8.10 µF capacitor together?smaller value µFlarger value

Answer 1

We will have the following:

The total capacitances you can make by connecting them in parallel and in series are:

Series:

`\begin{gathered} (1)/(C)=(1)/(4.45\mu F)+(1)/(8.10\mu F)\Rightarrow C=((4.45\mu F)(8.10\mu F))/((4.45\mu F)+(8.10\mu F)) \\ \\ \Rightarrow C=2.872111554...\mu F\Rightarrow C\approx2.87\mu F \end{gathered}`

Parallel:

`C=4.45\mu F+8.10\mu F\Rightarrow C=12.55\mu F`

So, the smaller value is:

`2.87\mu F`

And the largest value is:

`12.55\mu F`