Question

How many grams of oxygen are present in 76.8g of CO2

Answer 1

I think it would 55.8 grams but i could be wrong

Answer 2

Step-by-step explanation:

According to the mole concept there are
`6.022 * 10^(23) atoms` present in 1 mole of a substance.

Mathematically, 1 mole =
`6.022 * 10^(23)` atoms or molecules

Therefore, number of moles present in 76.8 g of
`CO_(2)` are as follows.

No. of moles =
`\frac{mass}{\text{molar mass}}`

=
`(76.8 g)/(44 g/mol)`

= 1.74 mol

As there are two atoms of oxygen are present in a molecule of
`CO_(2)`. Hence, calculate the number of oxygen atoms present in 1.74 mol of
`CO_(2)` as follows.

`2 * 1.74 mol * 6.022 * 10^(23)}atoms /mol`

=
`20.95 * 10^(23)` atoms

Thus, we can conclude that there are
`20.95 * 10^(23)` atoms of oxygen are present in 76.8g of
`CO_(2)`.