x²-3x-28÷(x²+10x+24)(x-5)
First, let's factorise x²-3x-28
x²-3x-28
x²-7x+4x-28
x(x-7) + 4(x-7)
(x-7)(x+4)
Next
We factorise; x² + 10x +24
x²+ 10x + 24
x² + 6x + 4x + 24
x(x+6) + 4(x+6)
(x+6)(x+4)
Now; let's plug them back into our original expression
(x+4) at the numerator will cancel-out (x+4) at the denominator
Hence;
we can leave the answer like this or open the bracket and then simplify
That is;
(x+6)(x-5) = x² -5x +6x - 30 = x² +x - 30
Plugging it back yields;