Question

HELP!!!

The number of students enrolled in a new course as a function of time can be represented by the function.

f(x)=(4)^x −1



What is the average increase in the number of students enrolled per hour between hours 2 and 4?



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Answer 1

is there a 120 if so i took the test

Explanation:

Answer 2

120

Explanation:

We are given that the function for the number of students enrolled in a new course is
`f(x) = 4^(x)-1`.

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

`A = (f(x)-f(a))/(x-a)`,

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) =
`f(x) = 4^(4)-1` = 255 and the number of students enrolled at 2 = f(2) =
`f(x) = 4^(2)-1` = 15

So, the average increase
`A=(f(4)-f(2))/(4-2)` =
`A=(255-15)/(4-2)` =
`A=(240)/(2)` = 120.

Hence, the average increase in the number of students enrolled is 120.