Given:
Focus (0, 4)
The standard equation for a parabola is :
y = a(x - h)² + k
But, h=0 and k=0
y = a(x - 0)² + 0
So we have y = ax² ------------------------------------(1)
We need to find the value of a.
But we know the focs is (0, 4)
Focus :(0, k+p)
P = 4
a = 1/4p
Substitute the value of p = 4 and evaluate
a = 1/4(4) = 1/16
Substitute a = 1/16 into equation(1)
That is;
y= 1/16 x²
Therefore, the parabola equation is:
y= 1/16 x²