Question

f(x) = x^2 + 6x + 81) What are the zeros of the function?Write the smaller x first, and the larger X second.smaller x =larger x =2) What is the vertex of the parabola?

Answer 1

f(x) = x^2 + 6x + 8

(x + 4) (x + 2)

The zeros are

x + 4 = 0 x + 2 = 0

x = -4 x = -2

The smaller is -4, the larger is -2

The vertex is (-3, -1)