How much is (OH-) when (H+) = 0.001m?a. 1x10^-3mb. 1x10^3mc. 1x10^-11md. 1x 10^11m

Mudin asked Feb 1, 2023

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Mudin asked Feb 1, 2023

by Mudin

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We know that the product of the concentrations of OH and H ions represents a constant.

$\lbrack H^+\rbrack\lbrack OH^-\rbrack=1*10^(-14)_{}$

Then, we solve for OH concentration.

$\lbrack OH^-\rbrack=(1*10^(-14))/(0.001)=1*10^(-11)M$

Therefore, the concentration of hydroxide is C. 1x10^-11 M.

Pronevich answered Feb 8, 2023

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