Question

I need help with this practice problem solving It is trig Please note-*It has an additional picture that I will send you, it is a graph that goes along, use the graph to complete the practice.*

Answer 1

`f(x)=\sin x+2`

Based on the sine equation above, the sine graph is shifted 2 units upward. Hence, one of the points we can find along the midline is (0, 2).

Based on the equation above too, the period is 2π. Since the horizontal distance between the maximum and minimum peak is half the period, the distance would be π.

Dividing π by 2, we get π/2. The nearest maximum peak would be located at x = π/2 whereas the nearest minimum peak would be located at x = -π/2.

Since the amplitude in the given equation is 1 then, the maximum peak is located at y = 3 whereas the minimum peak is located at y = 1.

To summarize, we have a point (0, 2) along the midline. The nearest maximum peak is at (π/2, 3). The nearest minimum peak is at (-π/2, 1).

The graph is: