Question

Suppose that the TSH (Thyroid Stimulating Hormone) levels among healthy individuals are normally distributed

Answer 1

Given the information:

Find the SD for 3.3, 5.9

`\begin{gathered} \sigma2=\sqrt[]{(1)/(n)\sum^(\infty)_(i\mathop=1)}(x\text{ i - u)\textasciicircum{}2} \\ \sigma2 \\ Substitute\text{ the information} \\ =\frac{(3.3-4.6)^2+\ldots+(5.9-4.6)^2_{}}{2} \\ \text{Simplify} \\ 3.3-4.6=-1.3*\text{-1}.3=1.69 \\ 5.9-4.6=1.3*2=1.69 \\ 1.69+1.69=3.38 \\ (3.38)/(2)=\text{3}.38/2=1.69=\sqrt[]{1.69}=1.3\text{ or}1.3*1.3 \end{gathered}`

SD = 1.3