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Two parallel lines are cut by a transversal as shown below. Suppose m<2= 128 degrees. Find m<5 and m<7

Two parallel lines are cut by a transversal as shown below. Suppose m<2= 128 degrees-example-1
User G Huxley
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1 Answer

14 votes
14 votes

From the diagram given we notice that angle 2 and angle 4 are vertical opposite angles, which means that the are equal, that is:


m\angle2=m\angle4

and hence we have that:


m\angle4=128

We also notice that angles 4 and 5 are consecutive interior angles, and since the lines are parallel this means that they have to add to 180°:


m\angle4+m\angle5=180

Plugging the value of angle 4 and solving for angle 5 we have:


\begin{gathered} 128+m\angle5=180 \\ m\angle5=180-128 \\ m\angle5=52 \end{gathered}

Finally, we notice that angles 5 and 7 are vertically opposite which means they are equal, hence:


m\angle7=52

Therefore, we conclude that:


\begin{gathered} m\angle5=52 \\ m\angle7=52 \end{gathered}

User Max Al Farakh
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