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Evaluate f(x)=3x*3+8x*2+5x-7 for remainder theorem

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Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

x-(3*x^3+8*x^2+5*x-7)=0

Step by step solution :Step 1 :Equation at the end of step 1 : x-((((3•(x3))+23x2)+5x)-7) = 0 Step 2 :Equation at the end of step 2 : x - (((3x3 + 23x2) + 5x) - 7) = 0 Step 3 :Step 4 :Pulling out like terms : 4.1 Pull out like factors :

-3x3 - 8x2 - 4x + 7 =

-1 • (3x3 + 8x2 + 4x - 7)
Checking for a perfect cube : 4.2 3x3 + 8x2 + 4x - 7 is not a perfect cube
Trying to factor by pulling out : 4.3 Factoring: 3x3 + 8x2 + 4x - 7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 3x3 - 7
Group 2: 8x2 + 4x

Pull out from each group separately :

Group 1: (3x3 - 7) • (1)
Group 2: (2x + 1) • (4x)
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