Question

The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? Round to the nearest hundredth. The equation that represents the problem is 48 = 96t - 16t2. Solve 16t2 - 96t + 48 = 0.

Answer 1

.55 first and then 5.45 you find it by finding the square root of six and finding it to be negative or positive on the right side of the equation

.55 & 5.45

Answer 2

`t = 0.56 s\\`

Explanation:

The given equation is

`s = v_(0) t - 16t^(2) \\48 ft = 96 (ft)/(s) t- 16t^2\\\\16t^2 -96t + 48 =0\\t^(2) - 6t + 3 = 0\\t = 0.56\\`