What is the molarity of a solution containing 289 g of sugar in a 2 L solution?
Molarity is defined like the number of moles of solute per liter of solution. We can use this formula to calculate the molar concentration of a solution:
molarity = moles of solute/volume of solution in L.
We already know the volume of solution in L but we are given the mass of solute.
volume of solution in L = 2 L
mass of solute = 289 g
We can convert the mass of solute into moles using the molar mass given.
molar mass of sugar = 342.2965 g/mol
moles of sugar = mass of sugar/(molar mass of sugar)
moles of sugar = 289 g/(342.2965 g/mol)
moles of sugar = 0.844 moles
Finally we can find the molarity of our solution:
molarity = moles of sugar/volume of solution in L
molarity = 0.844 moles/(2 L)
molarity = 0.422 M
Answer: the molarity of the solution is 0.422 M