Question

Object E has a mass of 4,800 kilograms. Object F has a mass of 600 kilograms. Both objects were placed on different planets so that their weights are equal.

The gravity acting on Object E is ________ times the gravity acting on Object F.

A) 1⁄8

B) 1⁄4

C) 1

D) 8

Answer 1

the answer is 8 because 4800 divided by 600 equals 8 so the right answer is d

Answer 2

Option A

Step-by-step explanation:

Mass of object E
`= 4,800` kilogram

Mass of object E
`= 600` kilogram

Let the gravity of planet on which object E is placed
`= g_(1)`

Gravity of planet on which object F is placed
`= g_(2)`

As we know -

Weight is equal to the product of mass and gravity.

The weight of both the objects is same after they are placed on planets with different gravity.

`M_(E) * g_(1) = M_(F) * g_(2) \\(M_(E))/(M_(F)) = (g_(2))/(g_(1)) \\`

Substituting the given values in above equation, we get -

`(4800)/(600) = (g_(2))/(g_(1)) \\(g_(2))/(g_(1)) = 8`

Thus, gravity acting on Object E is ___
`(1)/(8)`_____ times the gravity acting on Object F.