Question

I did some of it please help me do the rest

Answer 1

hello

from the graph given, the y-intercept of this graph is 1

the slope can be calculated using equation of slope of a line

`\begin{gathered} \text{slope(m)}=(y_2-y_1)/(x_2-x_1) \\ m=(2-0)/(2-0) \\ m=(2)/(2)=1 \end{gathered}`

the slope of this graph is equal to 1

let's write out the equation of a straight line

`\begin{gathered} y=mx+c \\ slope(m)=1 \\ \text{ intercept(c)=1} \\ y=(1)x+1 \\ y=x+1 \end{gathered}`

from the calculations above, the equation of the line is y = x + 1

y - intercept is that point in which the line crosses to the y-axis