Question

Two pools are being filled with water. To start, the first pool had 1700 liters of water and the second pool had 1271 liters of water. Wateris being added to the first pool at a rate of 26 liters per minute. Water being added to the second pool at a rate of 37 liters per minute.Let x be the number of minutes water has been added.Write an equation to show when the two pools would have thesame amount of water

Answer 1

To answer this question, first, we have to write two equations that describe the amount of water after x number of minutes and then, we will make those equations equal to each other.

The amount of water in the first pool, after x minutes, can be determined, using the following equation:

`T_1=1700+26x\text{.}`

The amount of water in the second pool, after x minutes, can be determined, using the following equation:

`T_2=1271+37x\text{.}`

An equation that shows when the pools will have the same amount of water is:

`1700+26x=1271+37x\text{.}`

Answer:

`1700+26x=1271+37x\text{.}`