Recall that when we do a reflection around the axis y = 1 (a horizontal line going through the point "1" in the y axis, each point gets reflected at the same distance they have to the y = 1 axis, but on the other side of the line.
So let's start with the point :
J = (2, 4) which is located at 3 units from the line y = 1 and above it. So during a reflection, it will keep the x-value, and chenge its y-value to 3 units BELOW the y=1 axis, leading to: (2 , -2)
Then (2, 4) goes to (2, -2)
Now the point: K = (-4, -2)
This one is located below the y = 1 axis , and 3 units below it, so during a reflection it will go 3 units above the y = 1 axis, and will keep the same x value:
(-4, -2) will go to (-4, 4)
finally the point L = (-1, 0)
This point is located below the y=1 axis in one unit, then its reflection will place it ONE unit above the y=1 axis. and again the x value will be kept intact:
(-1, 0) goes to (-1, 2)
Then we have found the reflection of all three vertices of the triangle.
Look at a reflection around the line y = 1, like if on that line you have a mirror and the points get reflected on the other side of it.
The x value will not change, but the y value will according to how far away from the "mirror" (y = 1 axis) they were initially.