70.1k views
5 votes
Find the output values of the exponential function g(x) = 4,096x for x = 0, 0.25, 0.50, 0.75, and 1.

2 Answers

5 votes

Hello,g(x)=4096^xg(0)=1g(0.25)=(2^12)^1/4=2^(12/4)=2^3=8g(0.50)=(2^12)^(1/2)=2^6=64g(0.75)=(2^12)^(3/4)=2^9=512g(1)=4096^1=4096.

User Matt Nelson
by
7.1k points
6 votes

Answer:

Output values for
g(x) = 4096^x

Explanation:

We are given the following information in the question:

We have to evaluate the given exponential function.


g(x) = 4096^x


g(0) = 4096^0 = 1\\\\g(0.25) = 4096^(0.25) = 8\\\\g(0.50) = 4096^(0.50) = 64\\\\g(0.75) = 4096^(0.75) = 512\\\\g(1) = 4096^1 = 4096

These are the required output values.

User Imraan
by
8.7k points