Given data:
* The force applied by Kinley is F = 3000 N.
* The work done on the softball is W = 100 kJ.
Solution:
The work done on the softball in terms of the force and the displacement is,
where d is the displacement of the softball,
Substituting the known values,
By simplifying,
Thus, the displacement of the ball is 33.3 meters or 0.03 km (in one significant figure).