C2H4 + O2 → CO2 + H2O
We want the same number of each element on each side.
Since there is only one compound on each side, we can start with carbon: When we double C02, we end up with 2 carbon atoms on each side.
When we double H20, we end up with 4 hydrogen atoms on each side.
The right side now contains 4 + 2 = 6 oxygen atoms, so we put a 3 in front of 02.
The result is:
C2H4 + 3O2 → 2CO2 + 2H2O