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What is the temperature (in K) of 16.45 moles of methane gas in a 4.95 L container at 4.68 atm?
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What is the temperature (in K) of 16.45 moles of methane gas in a 4.95 L container at 4.68 atm?

User Mehravish Temkar
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2 Answers

2 votes

Answer:

17.15

Step-by-step explanation:

User Eric Fong
by
8.4k points
5 votes
Using the ideal gas law: PV=nRT
P is pressure; V is volume; n is the amount in moles; R=0.082; T is temperature in K.

(4.68)*(4.95)=(16.45)*(0.0821)*T
Solve for T.
T=17.15
User BC Smith
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