Question

How to solve 3|x+6|-4≥8 ?

Answer 1

`\begin{gathered} x\text{ }\ge\text{ -2} \\ x\text{ }\le\text{ -10} \end{gathered}`Step-by-step explanation:

`3|x\text + 6\ge\text{ 8}`

Add 4 to both sides:

`\begin{gathered} 3|x\text + 6\ge\text{ 8 + 4} \\ 3|x\text + 6\ge\text{ 1}2 \end{gathered}`

Divide both sides by 3:

`\begin{gathered} \fracx\text + 6{3}\text{ }\ge\text{ }\frac{\text{1}2}{3} \\ |x\text \ge\text{ 4} \\ |x\text + 6 \end{gathered}`
`\begin{gathered} \text{ x + 6 }\ge\text{ 4} \\ x\text{ }\ge\text{ 4 - 6} \\ x\text{ }\ge\text{ -2} \\ OR \\ \text{-(x + 6) }\ge\text{ 4} \\ x\text{ + 6 }\le\text{ -4} \\ x\text{ }\le\text{ - 4 - 6} \\ x\text{ }\le\text{ -10} \end{gathered}`