Question

What are the x and y intercepts of: 6x + 3y = 12

Answer 1

You have the following equation:

`6x+3y=12`

To determine both x and y intercepts, proceed as follow:

x-intercept: makes y = 0 and solve for x in the given equation

`\begin{gathered} 6x+3(0)=12 \\ 6x=12 \\ x=(12)/(6)=2 \end{gathered}`

Hence, the xintercept is x = 2

y-intercept: makes x =0 and solve for y:

`\begin{gathered} 6(0)+3y=12 \\ 3y=12 \\ y=(12)/(3)=4 \end{gathered}`

Hence, the y-intercept is y = 4