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Junior slides across home plate during a baseball game. If he has a mass of 115 kg, and the coefficient of kinetic friction between him and the ground is 0.35, what is the force of friction acting on him?

User Phito
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1 Answer

7 votes

Weight Force of Junior = m g = 115kg x 9.81 m/s^2 = 1128.15N then compute for the friction force


Friction Force= WF x (coefficient of kinetic friction) = 1128.15N x 0.35 = 394.8525N or 395N

But you can compute in a straightway:

Solution:

= 115 x 9.81 x 0.35

= 394.85

= 395 N

It will still give the same results.

User Dzs
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