Answer:
The given equation has 2 real solutions.
Explanation:
If a quadratic equation is in the form of ax²+ bx + c = 0
The the roots of this equation will be real if (b²- 4ac) > 0
Now we have been given an equation x²- 9 = 0
This equation can be written as 1.x² + 0.x + (-9) = 0
Here a = 1
b = 0
and c = -9
Now we will calculate the value of (b² - 4ac)
(b² - 4ac) = 0 - (4)(1)(-9)
= 36 > 0
Therefore, The solution of the given equation will be 2 and real.
Now we factorize it to check the answer.
x² - 9 = 0
(x - 3)(x + 3) = 0
x -3 = 0
x = 3
Or (x + 3) = 0
x = -3
Therefore, equation has 2 real so;utions.