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A box contains 7 red, 12 green, 17 black and 9 yellow colored balls. If 2 balls are selectedwithout replacement, what is the probability obtains 1 green and 1 is black

User Luiz Rodrigo
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1 Answer

16 votes
16 votes

Okay, here we have this:

Considering the provided information, we are going to calculate the requested probability, so we obtain the following:

Probability of getting 1 green and 1 black = Probability of getting a green * Probability of getting a black

Probability of getting 1 green and 1 black = 12/45 * 17/44

Probability of getting 1 green and 1 black = 4/15 * 17/44

Probability of getting 1 green and 1 black = 17/165

Probability of getting 1 green and 1 black ≈ 0.10

Probability of getting 1 green and 1 black ≈ 10%

User Ljubadr
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