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An asteroid follows a hyperbolic path defined by the equation 16x2 − 9y2 = 576. If one of its foci is the sun’s position, the minimum distance between the asteroid and the sun is

User Ezra Free
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2 Answers

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I could give you some works
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An asteroid follows a hyperbolic path defined by the equation 16x2 − 9y2 = 576. If-example-1
User Xuan Tung Vu
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2 votes

Answer:

The minimum distance between the asteroid and the sun is 10 - 6 =4

Explanation:

The given hyperbolic path defined as
16x^(2)-9y^(2)=576

divide both the sides by 576,


(16x^(2))/(576)-(9y^(2))/(576)=(576)/(576)


(x^(2))/(36)-(y^(2))/(64)=1


(x^(2))/(36)-(y^(2))/(64)=1

The general equation of hyperbola is written as

;


(x^(2))/(a^(2))-(y^(2))/(b^(2))=1

Compare
(x^(2))/(36)-(y^(2))/(64)=1 with above mention equation

Here
a^(2)=36 \ \text{and} \ b^(2)=64

The distance between the asteroid and the sun is seen by figure -1


c^(2)=a^(2)+b^(2)=100 or
c^(2)=100

⇒c =10

The minimum distance between the asteroid and the sun is 10 -6 =4

An asteroid follows a hyperbolic path defined by the equation 16x2 − 9y2 = 576. If-example-1
User Esperanza
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