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Find the equation of the axis of symmetry and the coorinates of the vertex of the graph of the function y=4x^2+5x-1 a.)x=-5/8;vertex:(-5/8,-5 11/16) b.)x=5/8;vertex:(5/8,3 11/16) c.)x=5/8;vertex:(5/8,
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Sep 27, 2018
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Find the equation of the axis of symmetry and the coorinates of the vertex of the graph of the function y=4x^2+5x-1
a.)x=-5/8;vertex:(-5/8,-5 11/16)
b.)x=5/8;vertex:(5/8,3 11/16)
c.)x=5/8;vertex:(5/8, 4 5/8)
d.)x=-5/8;vertex:(-5/8,-2 9/16)
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Moki
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the right answer is
d)
x = -5/8; vertex: (-5,8, -2 9/16)
God bless!
Jarlax
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Oct 4, 2018
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Jarlax
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