Question

Which of the following equations has both −2−2minus, 2 and 222 as possible values of bbb?

Answer 1

Given that

There are two equations and we have to find the value of b.

Explanation -

The two equations one is quadratic and the other is cubic. These are

b^2 = 4

and b^3 = 8

Now, on solving it we have

`\begin{gathered} b^2=4 \\ b=√(4)=√(2*2) \\ b=\pm2 \\ \\ b^3=8 \\ b=\sqrt[3]{8}=\sqrt[3]{2*2*2} \\ b=2 \end{gathered}`

So the correct option is A

Final answer - Therefore the answer is b^2 = 4