Question

Evaluate the trigonometric function using its periods as an aid.

Answer 1

Weh ave the following:

`\sin \mleft(-(19\pi)/(6)\mright)`

we evaluate:

`\begin{gathered} \sin (-(19\pi)/(6))=-\sin ((19\pi)/(6))=-\sin ((7\pi)/(6))=-((1)/(2)) \\ \sin (-(19\pi)/(6))=(1)/(2) \end{gathered}`