Question

Stan needs a mine.Mine A is offering his services for an initial $90 in addition to $15 per hour. Mine B is offering her services for an initial $30 in addition to $35 per hour. When will the two mines charge the same amount of money?

Answer 1

Let the number of hours = x

Mine A is offering his services for an initial ​ $90 in addition to ​ $15 per hour.

So, Charges of A = 90 + 15x

Mine B is offering her services for an initial ​ $30 in addition to ​ $35 per hour.

so, Charges of B = 30 + 35x

The two mines charge the same amount of money when:

Charges of A = Charges of B

So,

`90+15x=30+35x`

solve for x

combine like terms

`\begin{gathered} 35x-15x=90-30 \\ 20x=60 \\ x=(60)/(20) \\ \\ x=3 \end{gathered}`

so, the two mines will charge the same amount of money when the number of hours = 3