How to find the antilogarithm of In x = 2 to the nearest ten-thousandths

Abo asked Apr 2, 2023

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18 votes

Abo asked Apr 2, 2023

by Abo

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18 votes

Given:

The expression is,

$\ln x=2$

But it is known that,

$\ln x=\log _ex$

Take antilog on both side,

$\begin{gathered} antilog_e\text{(log}_ex)=antilog_e(2) \\ \log ^(-1)_e(\log _ex)=e^2 \\ x=7.3890561 \\ \\ \end{gathered}$

Cleve answered Apr 7, 2023

by Cleve

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