First, we determine the number of moles of KCl which has a molar mass of 74.55 g/mol.
n = (25 g KCl)(1 mol/ 74.55 g KCl) = 500/1491 mol
Then, divide the number of calculated number of moles by the given molarity.
V = (500 / 1491 mol) / (0.750 mol/L)
V = 0.447 L
Answer: 0.447 L of solution