Find the sum of the first 10 terms of the following series, to the nearest integer.24,96,384, ...

Qvpham asked Jan 25, 2023

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35 votes

Qvpham asked Jan 25, 2023

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25 votes

$s\text{ }=\frac{a(r^n-1)^{}}{r-1}$

a = 24

n= 10

r = 96/24 = 4

Replacing:

$s=(24(4^(10)-1))/(4-1)=(24\cdot1,048,575)/(3)$

s = 8,388,600

Natan answered Jan 29, 2023

by Natan

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