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cellusIn a school, 10% of the students have green eyes. Findthe experimental probability that in a group of 4students, at least one of them has green eyes.The problem has been simulated by generating randomnumbers. The digits 0-9 were used. Let the number "9"represent the 10% of students with green eyes. A sampleof 20 random numbers is shown.79187910254613906075123023860793735930482816614759789732562161739436380659711430Experimental Probability = [?]%Enter

cellusIn a school, 10% of the students have green eyes. Findthe experimental probability-example-1
User LGT
by
3.1k points

1 Answer

13 votes
13 votes

First of all, we need to define Experimental probability and Theoretical probability.

• Theoretical probability, is what we expect to happen, but sometiimes it isn't what actually happens.

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• On the other hand, ,experimental probability, is what it actually happens when we conduct several tries.

In our sample, let's see how many "9" we have in each random number:

• Number 1: We have 1 nine (7918)

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• Number 2: We have 1 nine (7910)

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• Number 3: We don't have any 9 (2546)

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• Number 4: We have 1 nine (1390)

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• Number 5: We don't have any nine (6075)

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• Number 6: We don't have any nine (1230)

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• Number 7: We don't have any nine (2386)

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• Number 8: We have 1 nine (0793)

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• Number 9: We have 1 nine (7359)

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• Number 10: We don't have any nine (3048)

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• Number 11: We don't have any nine (2816)

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• Number 12: We don't have any nine (6147)

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• Number 13: We have 1 nine (5978)

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• Number 14: We don't have any nine (5621)

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• Number 15: We have 1 nine (9732)

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• Number 16: We have 1 nine (9436)

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• Number 17: We don't have any nine (3806)

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• Number 18: We have 1 nine (5971)

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• Number 19; We don't have any nine (6173)

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• Number 20: We don't have any nine (1430)

Now, we can count how many numbers have a nine:

Total is nine (numbers 1, 2, 4, 8, 9 13, 15, 16, 18)

Therefore, the experimental probability is:

Total number of 9 in the sample/Total of random numbers in the sample

9/20 = 0.45

Interpretation: The experimental probability of the sample is 45%

User Ruwantha
by
2.4k points