Question

Consider the line =−2x7y−1. Find the equation of the line that is parallel to this line and passes through the point −−4, 2.

Answer 1

We have: 2x+7y=−1

Let’s express this equation in terms of y:

⇒y=−27x−17

⇒ Gradient =−27

Parallel lines always have the same gradient:

⇒ Gradient of parallel lines =−27

Perpendicular lines have the negative reciprocal of the gradient:

⇒ Gradient of perpendicular lines =72

Step-by-step explanation:hope it helps