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5 votes
5 votes
Evaluate the expression (3d+9)^2-64 where d=1

User Exhuma
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1 Answer

19 votes
19 votes

\begin{gathered} \Rightarrow(3d+9)^2-64,\text{ where d=1} \\ \Rightarrow(3*1+9)^2-64 \\ \Rightarrow(3+9)^2-64 \\ \Rightarrow12^2-64 \\ \Rightarrow144-64 \\ \Rightarrow80 \end{gathered}

User Tooshel
by
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