Question

What is the approximate length of the midsegment parallel to BC.

A) 4.5
B) 4.9
C) 5.6
D) 6.2

Coordinates are B(-6,1) C(5,-1) please help  there is another point A(3,7) just in case u need it

Answer 1

The answer is C, 5.6 and I hope this is the question you wanted me to answer...

Answer 2

Explanation:

Alright, lets get started.

There are two points B (-6, 1) and C (5, -1)

The formula for distance between both points is :

`d = \sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2}`

`BC = √((5+6)^2+(-1-1)^2)`

`BC = √((11)^2+(-2)^2)`

`BC = √(121+5)`

`BC = √(125)`

`BC = 11.180`

So, its midsegment will be half of BC.

So midsegment =
`(11.180)/(2)=5.59`

Hence the answer is 5.6 : Answer

Hope it will help :)