Question

Simplify: Negative two and one-third minus negative ten and one-sixth

a Negative twelve and one-half
b Twelve and one-half
c Seven and five-sixths
d Negative seven and five-sixths


Determine the answer to (−3) + (−5) and explain the steps using a number line. please give example and how you did it

Use absolute value to express the distance between −12 and −15 on the number line.

a |−12 − (−15)| = −27
b |−12 − (−15)| = −3
c |−12 − (−15)| = 3
d |−12 − (−15)| = 27

please help im failing and its stressing

Answer 1

Its A its right

Explanation:

not C

Answer 2

`1.\rightarrow -2 (1)/(3)-(-10) (1)/(6)\\\\\rightarrow (-7)/(3) -(-61)/(6)\\\\\rightarrow (-14+61)/(6)\\\\\rightarrow (47)/(6)\\\\\rightarrow 7(5)/(6)`

Option C→Seven and five-sixths

2.

(-3) +(-5)

Mark -3 and -5 on the number line.Move 5 units left of -3 to reach at -8.That is required sum.

3.

Distance between −12 and −15 on the number line is given by

|-12 -(-15}| or |-15 -(-12)|

=|-12+15| or |-15+12|

=|3| or |-3|

=3 units

Option C

|−12 − (−15)| = 3