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8. First drop down menu answer choices A. Less than B. Equal to C greater than Second drop down answer choices A. 10 B. 20 C. 31.4 D. 15.7Third drop down answer choices A. 20 B. 10C. 31.4 D. 15.7

8. First drop down menu answer choices A. Less than B. Equal to C greater than Second-example-1
User Jameslol
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1 Answer

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9 votes

ANSWER and EXPLANATION

To find the person with the larger paper, we have to find the area of both pieces of paper.

Jada's paper is a rectangular-shaped paper that measures 5 inches by 4 inches.

To find the area of the paper, we have to find the product of its side lengths.

The area of Jada's paper is:


\begin{gathered} A=5\cdot4 \\ A=20in^2 \end{gathered}

Han's paper is shaped like the sector of a circle. The area of the sector of a circle is:


A=(\theta)/(360)\cdot\pi r^2

where θ = angle of the sector

r = radius

We have to find the measure of the angle of the sector by applying the formula for the length of an arc:


\begin{gathered} L=(\theta)/(360)\cdot2\pi r \\ \Rightarrow2\pi=(\theta)/(360)\cdot2\pi\cdot5 \\ \Rightarrow\theta=(2\pi\cdot360)/(2\pi\cdot5) \\ \theta=72\degree \end{gathered}

Hence, the area of Han's paper is:


\begin{gathered} A=(72)/(360)\cdot\pi\cdot5^2 \\ A=15.7in^2 \end{gathered}

As we can see, Jada's rectangular piece of paper has an area that is greater than Han's piece of paper shaped like a sector. The area of Jada's piece of paper is 20 in² and the area of Han's piece of paper is 15.7 in²

User Neves
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