Question

What is a factor of x2+8x-48

Answer 1

To factorize a polynomial of general form ax2+bx+c, one should divide middle term bx in two parts, whose sum is b and product is a×c.

So for x2−8x−48, we should divide −8x in two parts which add up to −8 and whose product is 1×(−48)=−48.

A few trial indicate them to be −12 and 4. Hence

x2−8x−48=x2−12x+4x−48 or

x(x−12)+4(x−12) or

(x+4)(x−12)

Answer 2

(x-4)(×+12)
The answer is (x-4)(x+12)
This is factored.
hope this helps!